Maxwell’s Equations, Transmission lines, the Capacitor, Radio and the Atom as Charged Capacitor
Nigel Cook
UPDATE. See following post and its comments section:
http://electrogravity.blogspot.com/2006/01/solution-to-problem-with-maxwells.htmlA time-varying current results in radio emission. Neither Catt nor anyone else has measured the fields in the space between two conductors as a TEM wave passes: they have only measured induced currents in other conductors. Radio emission is occurring at the front of a logic step! Catt got the 'Catt anomaly' wrong by relying on a book published in 1893 which ignored the step effects at the front of the TEM wave. Asserting ignorance is wrong. At the front of a logic step, current rises (in accepted picture) and this results in radio emission. Since each conductor is oppositely charged and carries an opposite current, the radio emission from each conductor (acting as aerials) is exactly out of phase with the other and so completely cancels that from the other as seen at a large distance. So there is no energy radiated to large distances! The only radio emission of energy occurs from each conductor to the other.
Maxwell wrote 'displacement current' in terms of electric field strength. However, as the voltage rises at front of the logic step, current rises. Maxwell should have written the extra current (displacement current in vacuum) equation in terms of the ordinary (conductor based) current, which means 'displacement current' is radio. Maxwell: displacement current i = e.dE/dt = e(v/ct^2), where e is permittivity and v is uniform voltage rise over time t. What I'm saying is that the mutual radio emission causes the front of the logic step (the rising part) to propagate. Each conductor induces current in the other! It is fact that the inverse-square law doesn't apply: there is no net radio transmission beyond the system because of perfect interference, as the current rise in each conductor is the exact opposite of that in the other one so the radio transmissions from each conductor exactly cancels the other outside the transmission line!
(1) an aerial is a single conductor and does radiate radio as the current applied varies, we know a single conductor can't propagate a constant current because its inductance is infinite (which is a mechanism for Kirchoff's law), (2) if the capacitor is a transmission line, as stated before, the radio emission due to each conductor (capacitor plate) is the exact opposite of the other, and cancels out as seen from a distance. What I'm saying is that to resolve the Catt anomaly the TEM wave step needs to be analysed in two parts, first where the current is increasing (which is omitted from today's treatment), and second where the current is static (which the current treatment does describe, using steady magnetic and electric fields). If the current rise (step front) was vertical, "displacement current" there (however you think of it) would be infinite, and since "displacement current" is an invention by Maxwell to retain continuity of current flow across the vacuum, you would then have the paradox of a finite current flowing along one wire turning into an infinite "displacement current" across the vacuum and then returning to a finite displacement current in the other wire. The true rise is not vertical, because the current does not rise from 0 to i instantly at any point on a conductor as the step passes by. It can be very great. The standard treatment of radio shows that radio emission is proportional to the variation rate of the net current di/dt in a conductor. "Displacement current" is the radio exchange process where the front of the TEM wave in each conductor swaps energy by radio (or electromagnetic pulse, if you prefer to reserve "radio" for sine wave shaped electromagnetic waves, as Kevin does). The wires must swap energy across the vacuum to propagate; each one is inducing the current in the other one. This is why the TEM wave goes at the speed of light in the vacuum between the conductors.